=16t^2+312

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Solution for =16t^2+312 equation: 



=16t^2+312

We move all terms to the left:

-(16t^2+312)=0

We get rid of parentheses

-16t^2-312=0

a = -16; b = 0; c = -312;
Δ = b2-4ac
Δ = 02-4·(-16)·(-312)
Δ = -19968
Delta is less than zero, so there is no solution for the equation

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